सादृश्यता टेस्ट टाइप 3

Second term = 4 × First term
Fourth term = 4 × Third term

11 : 17 alternate prime number (skipping 13)
19 : 29 alternate prime number (skipping 23)

Second term = (First term)³
∴ Fourth term = (Third term)³

12 = 3² + 3, 30 = 5² + 5 :
20 = 4² + 4 : ? = 6² + 6

3 = 2² – 1,10 = 3² + 1
8 = 3² – 1,? = 4² + 1

13 and 19 are primes with 17 left out in between.

48 = 7² – 1, 122 = 11² + 1 :
168 = 13² – 1, ? = 17² + 1

(2 + 1 + 1) + 5 = 3 + 3 + 3
(3 + 5 + 6) + 5 = 3 + 8 + 8

The relationship is (2x – 4) : x